DFS spanning tree

Time Limit: 3000ms
Memory Limit: 65536KB
This problem will be judged on HDU. Original ID: 4582
64-bit integer IO format: %I64d      Java class name: Main

Description

Consider a Depth-First-Search(DFS) spanning tree T of a undirected connected graph G, we define a T-Simple Circle as a path v1, v2, ..., vk (v1 = vk) in G that contains at most one edge which not belongs to the DFS spanning tree T.
Given a graph G, we process DFS on G starting from vertex 1 and get a DFS spanning tree T, then you should choose some edges of G so that all T-Simple Circles contains at least one edge that you choose.
Please minimize the number of edges you choose.

Input

There are at most 100 test cases.
For each case, the first line contains two integers n and m denoting the number of vertices and edges. The vertexes are numbered from 1 to n.
The following m lines describe the graph. Each line contains two integers xi and yi, denoting an edge between vertex xi and yi(xi ≠ yi).
Note that the first n-1 edges of input construct a DFS spanning tree T which is generated by DFS from vertex 1.
Input ends with n = 0 and m = 0
(1 <= n <= 2000, 1 <= m <= 20000, 1 <= xi, yi <= n)

Output

For each case, output the number of minimal edges that you choose.

Sample Input

4 5
1 2
4 2
3 2
1 3
4 1
10 14
1 2
2 9
1 3
3 4
4 10
3 5
5 7
5 8
3 6
9 1
1 10
1 6
7 3
8 3
0 0

Sample Output

1
3

Source

Language: 
Theme: 
Share Code? 

Powered by NB231 | Current Style: .