We consider the Fibonacci sequence f where f(0) = 0, f(1) = 1 and f(n) = f(n - 1) + f(n - 2) for n ≥ 2. For given x(0), one can define another sequence x that x(n) = f(x(n-1)). Now you need to find the minimum n such that x(n) ≡ x(0) (mod p).
The first line contains an integer T indicating the number of test cases. Then for each test case, a line consists of two integers x(0) and p where 0 ≤ x(0) ≤ $10^9$ and 1 ≤ p ≤ 200000.
For each test, output the minimum n in a line, or -1 if it is impossible.